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LeetCode 586. Customer Placing the Largest Number of Orders SQL Solution

Problem

LeetCode SQL Problem

  1. Customer Placing the Largest Number of Orders

orders table

order_numbercustomer_numberorder_daterequired_dateshipped_datestatuscomment
112017-04-092017-04-132017-04-12Closed
222017-04-152017-04-202017-04-18Closed
332017-04-162017-04-252017-04-20Closed
432017-04-182017-04-282017-04-25Closed

Solution

Find the Customer Placing the Largest Number of Orders
SELECT customer_number
FROM orders
GROUP BY customer_number
ORDER BY COUNT(*) DESC
LIMIT 1;

This MySQL query retrieves the customer number of the customer who has placed the highest number of orders. It achieves this by grouping the orders based on customer numbers, counting the number of orders for each customer, ordering the groups in descending order by the order count, and then limiting the result to only one row.

Here's a breakdown of the query:

  1. SELECT customer_number: This part of the query specifies that you want to select the "customer_number" column from the "orders" table. This column presumably contains unique identifiers for customers.

  2. FROM orders: This part indicates that you are fetching data from the "orders" table, assuming it contains information about customer orders.

  3. GROUP BY customer_number: This clause groups the rows in the "orders" table based on the unique values in the "customer_number" column. Each group represents orders placed by the same customer.

  4. ORDER BY COUNT(*) DESC: This clause specifies how the grouped results should be ordered. It orders the groups in descending order based on the count of rows in each group. The COUNT(*) function counts the number of rows (orders) in each customer group. This ensures that customers with the highest order count will appear first.

  5. LIMIT 1: This clause restricts the result to only one row. Since the groups are ordered by order count in descending order, this effectively retrieves the customer number of the customer with the highest number of orders.

In summary, the query identifies the customer who has placed the most orders by grouping orders by customer number, counting the orders for each customer, ordering the groups by order count in descending order, and then limiting the result to a single row using the LIMIT 1 clause.

Query Output

customer_number
3